Explanation

Explanation for the Analytical Reasoning Quiz 04

This is the detailed explanation for the Analytical Reasoning Quiz 04 .


1. “In case T and Z are the individuals serving on committee B, how many of the nine individuals should serve on committee C?”

Given:

  • Committee B needs 2 members, and in this case, T and Z are on Committee B.

  • Committee A needs to have exactly one more member than Committee B, which means Committee A must have 3 members.

  • The total number of people is 9. If Committee B has 2 members and Committee A has 3 members, then Committee C must have the remaining members:

    • 9−(2 from B+3 from A)=4 members for Committee C9 – (2 \text{ from B} + 3 \text{ from A}) = 4 \text{ members for Committee C}.

Correct answer: 4

There are 4 members who will serve on Committee C.


2. “Of the nine individuals, the largest number that can serve together on committee C is?”

Given:

  • Committee C can have no more than 4 members because the other two committees (A and B) already take up the remaining members.

  • Committee B is fixed at 2 members (as stated by the rules), and Committee A must have 3 members.

  • This leaves 4 members who must serve on Committee C.

Correct answer: 4

The largest number of people that can be assigned to Committee C is 4.


3. “In case R is the only individual serving on committee B, which among the following should serve on committee A?”

Given:

  • R is the only member of Committee B. Therefore, Committee B must have one more member (since it should have exactly two members).

  • T, S, and R cannot serve on Committee B (as stated in the rules).

  • Thus, T and S must serve on Committee A.

Correct answer: T and S

Since T and S are the only ones who can be placed on Committee A (given the restrictions), they should serve together on Committee A.


4. “In case any of the nine individuals serves on committee C, which among the following could not be the candidate to serve on committee A?”

Given:

  • Z, Y, and X cannot serve on Committee A (as per the restrictions in the problem).

  • This means any combination that includes Z, Y, or X cannot serve on Committee A.

  • We need to look at each pair and see if Z, Y, or X is included:

    • X and V: X cannot serve on Committee A, so this combination is not possible.

    • Z and Y: Both Z and Y cannot serve on Committee A, so this is not allowed either.

    • Y and V: Y cannot serve on Committee A, so this pair is not allowed.

    • Z and W: Z cannot serve on Committee A, so this combination is invalid.

    • Y and U: Y cannot serve on Committee A, so this combination is also invalid.

Thus, the only pair that would not be allowed on Committee A is Z and Y because they are both restricted from serving there.

Correct answer: Z and Y

Z and Y cannot both serve on Committee A.


5. “Among the following combinations which could constitute the membership of committee C?”

Given:

  • Committee C can have members who are not restricted from serving on Committee C.

  • Z, Y, and X cannot serve on Committee C (based on the restrictions).

  • W, V, and U can serve on Committee C.

Let’s evaluate the options:

  1. X and U: X cannot serve on Committee C (due to restriction), so this combination is invalid.

  2. Y, X, and W: Y and X are restricted from Committee C, so this combination is invalid.

  3. Y and T: Y is restricted from Committee C, so this combination is invalid.

  4. Z, X, U, and R: Z and X are restricted from Committee C, so this combination is invalid.

  5. W, V, and U: W, V, and U are all allowed to serve on Committee C, so this combination is valid.

Correct answer: W, V, and U

This is the only valid combination for Committee C.


Summary of Correct Answers:

  1. 4 – In case T and Z serve on Committee B, 4 should serve on Committee C.

  2. 4 – The largest number that can serve together on Committee C is 4.

  3. T and S – If R is the only member of Committee B, T and S should serve on Committee A.

  4. Z and Y – Z and Y cannot serve on Committee A.

  5. W, V, and U – This is the valid combination for Committee C.

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