Algebra Quiz 03

If x=3 is solution of x² + kx + 15, value of k is

None of above

k = 8, x = 3

k = -8,x = 5

k = 6, x = 5

Correct! Wrong!

9a² - 4 gives

54a - 32

9a + 12

(3a + 2)(3a - 2)

(4a + 13)(4a - 13)

Correct! Wrong!

Factorize x² + 8x + 12

(x + 3)(x + 4)

3x + 12

3x - 12

(x + 2)(x + 6)

Correct! Wrong!

(a + 2b)² - (a + 2b)(3a - 7b) by factorization gives

None of above

5b - 4a

(a + 2b)(9b - 2a)

a - 3b + 4ab

Correct! Wrong!

Factorize 2x²y² + 5xy - 12

(2xy - 3)(xy + 2)

(2xy - 3)(xy + 4)

3xy - 12x + 9y

4y - 3xy

Correct! Wrong!

Expansion of (x + 3y)(x - y) gives

x + 3y - 2xy

3y - 42x

x² + 2xy - 3y²

-2y + 3x

Correct! Wrong!

Whole number such that twice of its square added to itself gives 10

2

8

10

5

Correct! Wrong!

39² + 78 + 1 using algebraic identities gives

1200

1600

500

1700

Correct! Wrong!

Two positive numbers differ by 5 and square of their sum is 169 are

5,6

4,9

3,7

2,4

Correct! Wrong!

Expansion of 2x(x + 2y) + 3x(2x - 3y) yields

8x² - 5xy

8x - 5y

3y - 2y

none of above

Correct! Wrong!

If x=3 is solution of x² + kx + 15, value of k is

9a² - 4 gives

Factorize x² + 8x + 12

(a + 2b)² - (a + 2b)(3a - 7b) by factorization gives

Factorize 2x²y² + 5xy - 12

Expansion of (x + 3y)(x - y) gives

Whole number such that twice of its square added to itself gives 10

39² + 78 + 1 using algebraic identities gives

Two positive numbers differ by 5 and square of their sum is 169 are

Expansion of 2x(x + 2y) + 3x(2x - 3y) yields

About the author

Muhammad Arslan

If x=3 is solution of x² + kx + 15, value of k is

9a² - 4 gives

Factorize x² + 8x + 12

(a + 2b)² - (a + 2b)(3a - 7b) by factorization gives

Factorize 2x²y² + 5xy - 12

Expansion of (x + 3y)(x - y) gives

Whole number such that twice of its square added to itself gives 10

39² + 78 + 1 using algebraic identities gives

Two positive numbers differ by 5 and square of their sum is 169 are

Expansion of 2x(x + 2y) + 3x(2x - 3y) yields

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About the author

Muhammad Arslan